Conservation of angular momentum

AI Thread Summary
When a block is dropped onto a rotating disc, both will eventually rotate together at a new, slower angular velocity. The discussion centers on the force responsible for initiating the block's rotational motion. Friction is identified as a key factor, as it not only slows down the disc but also enables the block to start rotating. An experiment is suggested involving a pulley system to demonstrate how torque is generated by the weight of a descending bob, which influences the disc's motion. Overall, friction plays a crucial role in both starting and affecting the motion of the block on the disc.
Leong
Messages
379
Reaction score
2

Homework Statement


When a block is dropped to a disc that is rotating with a constant angular velocity about its centre, at the end, we know that both of them will rotate with the same new angular velocity which is slower than the previous one.
Question: What is the force that makes the block to start rotating?


Homework Equations





The Attempt at a Solution



Is it friction? Can friction actually starts a motion of an object? I know that it is friction that slows down the disc but what force makes the object to start its rotational motion? I don't know.
 
Physics news on Phys.org
Leong said:

Homework Statement


When a block is dropped to a disc that is rotating with a constant angular velocity about its centre, at the end, we know that both of them will rotate with the same new angular velocity which is slower than the previous one.
Question: What is the force that makes the block to start rotating?
Assemble the disc on a table and create a little pulley on the edge of the table. Tie a bob of some mass around some string and arrange this over the pulley. Then wrap the other end of the string around the axle of the disc. When the string unwinds, the bob will descend to the floor and it's weight will create a downward force, F, at some distance r, thus creating a torque, which turns the disc.

Is it friction? Can friction actually starts a motion of an object?.
If it weren't for friction, we wouldn't be able to walk.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top