To find the maximum height and kinetic energy of an arrow fired at a 45-degree angle with an initial velocity of 15 m/s, one must analyze the motion using the equations for kinetic energy (Ek = 1/2mv^2) and potential energy (Ep = mgh). The arrow's initial kinetic energy can be calculated using its mass and initial velocity. At maximum height, the vertical component of the velocity becomes zero, while the horizontal component remains unchanged, allowing for the calculation of potential energy at that height. Understanding the conservation of energy principles is crucial, as the initial kinetic energy converts to potential energy at the peak of the trajectory. The discussion emphasizes the importance of breaking down the velocity into its components to solve the problem accurately.