A spring of negligible mass has force constant k = 1800N/m .
You place the spring vertically with one end on the floor. You then drop a book of mass 1.20kg onto it from a height of 0.500m above the top of the spring. Find the maximum distance the spring will be compressed.
Ki + Ui = Kf + Uf
The Attempt at a Solution
First I calculated the velocity of the block when it makes contact with the spring and I got v = 3.96 m/s.
Then I used conservation of energy to find the spring compression distance by setting the point where the block makes contact with the spring to be zero (y=0).
Ki = Uf
(1/2)mvi2 = (1/2)kx2 - mgx
Then I substituted the values in and had to use the quadratic formula to find x which I got x = 0.10898m or x = -0.0959.
I used the negative x value because the spring is being compressed downward, but my answer is still incorrect somehow.