Calculating Velocity of a Block Shot from a Spring Gun

In summary, a 0.75 kg block is shot from a spring gun on a frictionless table with a height of 1.04 m. The spring has a constant of k = 28 N/m and is compressed by 0.23 m. The question is how fast will the block be going when it hits the ground? When solving for velocity using (1/2)*kx^2 = (1/2)mv^2, the answer comes out to be 4.3 m/s, but the correct answer is 4.73 m/s. The mistake may lie in not accounting for the height of the table in the calculation. Additionally, the correct value for k is 28 N/m, not
  • #1
Aggie
21
0
A block, mass 0.75 kg, is "shot" from a spring gun from a table. The table has a height 1.04 m and is frictionless. If the spring has k=28 N/m and is originally compressed 0.23 m, how fast will the block be goign when it hits the ground?


(1/2)*kx^2 = (1/2)mv^2 ?



I got 4.3 m/s but the answer is 4.73 m/s
 
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  • #2
If you show us your work, we can say where you've gone wrong.
 
  • #3
(23*0.23^2)/2= (0.75*9.8*1.04)+(0.7*v^2)/2
 
  • #4
Hint: you have to "count in" the height of the table somehow in your calculation.
 
  • #5
Aggie said:
(23*0.23^2)/2= (0.75*9.8*1.04)+(0.7*v^2)/2
Are you sure?? You need to find the velocity at the bottom and not at 1.04m. Also, k = 28N/m, not 23.
 

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