- #1

- 21

- 0

(1/2)*kx^2 = (1/2)mv^2 ?????????????

I got 4.3 m/s but the answer is 4.73 m/s

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- Thread starter Aggie
- Start date

- #1

- 21

- 0

(1/2)*kx^2 = (1/2)mv^2 ?????????????

I got 4.3 m/s but the answer is 4.73 m/s

- #2

- 2,076

- 2

If you show us your work, we can say where you've gone wrong.

- #3

- 21

- 0

(23*0.23^2)/2= (0.75*9.8*1.04)+(0.7*v^2)/2

- #4

radou

Homework Helper

- 3,120

- 7

Hint: you have to "count in" the height of the table somehow in your calculation.

- #5

- 2,076

- 2

Are you sure?? You need to find the velocity at the bottom and not at 1.04m. Also, k = 28N/m, not 23.(23*0.23^2)/2= (0.75*9.8*1.04)+(0.7*v^2)/2

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