- #1
Carpe Mori
- 19
- 0
ok i this question has been asked but whoever asked it did not show work therefore did not have it answered so here we go my attempt!
Show that on a roller coaster with a circular vertical loop the difference in your apparent weight at the top of the loop and the bottom of the loop is 6 g's that is 6 times your weight. ignore friction.
h = height of start of roller coaster
R = loop's radius
PE = KE
a = v^2/R
at the top of loop: mgh = mg2R + .5mv^2
solved for velocity v^2 = 2g(h-2R)
centripital acceleration is a = v^2/R ---> a = 2g(h-2R)/R
also i knew from another problem that minimum h had to be 2.5R to be able to go through the whole loop and stay on track so...
a = g? haha yeah i am lost i have no idea what to do. I am trying to teach this course to myself and i am really struggling without a teacher. Please help?
Homework Statement
Show that on a roller coaster with a circular vertical loop the difference in your apparent weight at the top of the loop and the bottom of the loop is 6 g's that is 6 times your weight. ignore friction.
h = height of start of roller coaster
R = loop's radius
Homework Equations
PE = KE
a = v^2/R
The Attempt at a Solution
at the top of loop: mgh = mg2R + .5mv^2
solved for velocity v^2 = 2g(h-2R)
centripital acceleration is a = v^2/R ---> a = 2g(h-2R)/R
also i knew from another problem that minimum h had to be 2.5R to be able to go through the whole loop and stay on track so...
a = g? haha yeah i am lost i have no idea what to do. I am trying to teach this course to myself and i am really struggling without a teacher. Please help?
