(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A large plate is dropped and breaks into three large pieces. The pieces fly apart parallel to the floor. As the plate falls, its momentum has only vertical components, none parallel to the floor. After the collision, the component of momentum parallel to the floor must remain zero since the external force acting on the plate has no parallel component. As viewed from above, piece one has a component velocity of 3m/s at an angle of 115 degrees to the horizontal. Piece two has a velocity of 1.79m/s at an angle of 45 degrees. The third has a velocity of 3.07m/s at -90 degrees and a mass of 1.3 Kg.

What is the mass of the other two pieces?

2. Relevant equations

P=mv

J=F[tex]\Delta[/tex]t=[tex]\Delta[/tex]p

conservation of momentum

3. The attempt at a solution

First, I drew a picture.

http://www.imagecross.com/image-hosting-viewer-01.php?id=8714untitled1.JPG

then I solved for the velocity in the X and Y directions using sin and cos

I am stuck on the meat of the problem

(x direction)0=mv1+mv2+mv3

=m1.26+m1.26+1.3(0)

y direction 0=m2.71+m1.26+1.3(3.07)

I am lost at this point.

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# Conservation of momentum and Impulse

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