Conservation of Momentum and Kinetic Energy

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SUMMARY

The discussion centers on the conservation of momentum and kinetic energy during a collision involving a glider and a rubber band bumper. The data indicates that momentum experienced a 5% change, while kinetic energy showed a 10%-15% change, leading to the conclusion that momentum is conserved, but kinetic energy is not. The calculations provided demonstrate that as velocity increases, the percentage of kinetic energy lost also increases, suggesting that the collision is not perfectly elastic despite occurring on a frictionless surface.

PREREQUISITES
  • Understanding of basic physics concepts such as momentum and kinetic energy
  • Familiarity with the equations for kinetic energy (K = 1/2*m*v²) and momentum (p = m*v)
  • Ability to calculate percentage change in values
  • Knowledge of elastic and inelastic collisions
NEXT STEPS
  • Study the principles of elastic and inelastic collisions in detail
  • Learn how to calculate conservation of energy in different types of collisions
  • Explore the effects of mass and velocity on kinetic energy loss
  • Investigate real-world applications of momentum conservation in physics experiments
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators preparing lab reports on momentum and energy conservation.

Blangett
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Homework Statement



I was wondering if a glider hits a rubber band bumper is kinetic energy conserved? I can't tell if the data I have supports conservation or loss. I am writing a lab report and data shows that momentum had around a 5% change. Kinetic energy had a 10%-15% change. Momentum is always conserved in a collision so I can conclude its conservered in this case. What is worrying me is that my data is wrong because momentum had a 5% change, I am not sure at what percentage makes it not conserved. I think Kinetic energy is not conserved in this case. Am I right?

Mass ~ 0.1833

Velocity Before
v1=0.4109
v2=0.4327
v3=0.5959


Velocity After
v1= 0.3898
v2= 0.4083
v3= 0.5462




Homework Equations



K= 1/2*m*v2

p= m*v

Percentage of change 1 - (kinetic before/kinetic after)

percentage of change momentum 1 - (momentum before/momentum after)



The Attempt at a Solution




(.013925671/0.015474070) = .89999 so 90% is conservered a 10% change

(0.01527887/0.017159564) = .890 so 89% is conserved a 11% change

(0.027342351/0.032544623) = .840 so 86% is conserved a 14% change

It seemed that the larger the velocity the more kinetic energy is lost. I am worried my conclusion is completely inaccurate.
 
Physics news on Phys.org
Do you think your situation is perfectly elastic?
 
I suppose its supposed to be since its a frictionless surface.
 

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