Conservation of Momentum of a plate

AI Thread Summary
The discussion focuses on a physics problem involving the conservation of momentum after a plate shatters into three pieces. The speed of the third piece is calculated to be v3 = vsqrt(2). For determining the direction of the third piece, there is confusion over whether to use arctan(z/x) or arctan(y/x), with the latter yielding a direction of 135 degrees and the former 234.74 degrees. The need for an equation to find the direction is debated, with suggestions that a vector diagram could suffice. The conversation highlights the complexities of applying momentum conservation principles in two-dimensional motion scenarios.
henry3369
Messages
194
Reaction score
0

Homework Statement


A plate drops onto a smooth floor and shatters into three pieces of equal mass. Two of the pieces go off with equal speeds v at right angles to one another.

1. Find the speed of the third piece.

2. Find the direction of the third piece. Assume the motion of the two pieces at right angles to one another is in the positive x and y directions.

Homework Equations


vf(m1 + m2 + m3) = m1v1+m2v2+m3v3

The Attempt at a Solution


So I solved #1 to be v3 = vsqrt(2).

For #2, should the direction of the third piece be theta = arctan(z/x) or arctan(y/x)? I found some attempt of the solution online and they used arctan(y/x), which confuses me because wouldn't that find the resultant vector of the x and y component?

If you do arctan(y/x) you get theta = 135 degrees while arctan(z/x) gives 234.74 degrees. Which one is correct?
 
Physics news on Phys.org
I don't even understand why you would need ANY equation to tell you the answer. Draw a vector diagram and it should be obvious. The SPEED will require an equation but not the direction, unless I am seriously misunderstanding something about the problem statement.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top