Conservation of momentum of astronaut in her space suit

AI Thread Summary
An astronaut in a space suit, with a total mass of 91.3 kg, throws her 12.0 kg oxygen tank at 8.50 m/s to propel herself back to her spacecraft after losing her tether. The conservation of momentum equation is applied to determine her final velocity, which is calculated to be 1.112 m/s. The astronaut needs to calculate the maximum distance she can drift from the spacecraft within 1.60 minutes while considering that she is in free space, where gravitational effects are negligible. After correcting calculations and understanding that no significant external forces act on her, the maximum distance she can reach is determined to be approximately 123.5 meters. This scenario exemplifies Newton's Third Law, where the force exerted on the tank results in an equal and opposite force propelling the astronaut towards the spacecraft.
mandy9008
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Homework Statement


An astronaut in her space suit has a total mass of m1 = 91.3 kg, including suit and oxygen tank. Her tether line loses its attachment to her spacecraft while she's on a spacewalk. Initially at rest with respect to her spacecraft , she throws her oxygen tank of mass m2 = 12.0-kg away from her spacecraft with a speed v = 8.50 m/s to propel herself back toward it (see figure).
p6-25.gif


(a) Determine the maximum distance she can be from the craft and still return within 1.60 min (the amount of time the air in her helmet remains breathable).
(b) Explain in terms of Newton's laws of motion why this strategy works.


Homework Equations


m1v1i + m2v2i = m1v1f + m2v2f


The Attempt at a Solution


a. (91.3 kg)(0 m/s) + (12.0 kg)(0 m/s) = (91.3 kg)v1f + (12.0 kg)(8.50 m/s)
v1f=1.112 m/s
b. When the astronaut throws her oxygen tank, she applies a force onto it. At the same time, the oxygen tank is applying a force onto her, which pushes the astronaut towards the space ship. This is an example of Newton's Third Law.
 
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You calculate the speed correctly in part (a), but that's not what the problem is asking for. You need to find a maximum distance.

Part (b) is OK.
 
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all
 
mandy9008 said:
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all

I think you need to consider projectile motion concept.
 
mandy9008 said:
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all

The astronaut is in free space, not on the surface of Earth! Is there any force acting on she after she has thrown the oxygen tank away? This is not a projectile motion.


ehild
 
okay so, do i need to find her acceleration and use that in place of g?
 
mandy9008 said:
okay so, do i need to find her acceleration and use that in place of g?

You know that acceleration is force over mass. What can exert force on the astronaut in free space?

ehild
 
I don't know. I know that it is not gravitational, since you said that I can't use 9.8 m/s^2
 
Is gravitational acceleration 9.8 m/s^2 everywhere in the world? On the surface of the Moon for example? Have you seen films about astronauts walking on the Moon?

There is gravitational interaction between any objects with mass. Do you know the formula?

ehild
 
  • #10
mandy9008 said:
okay, so I need to solve for change in x, right?
x=vt + 1/2 gt^2
x= (1.118 m/s)(96 s) + 1/2 (9.8 m/s^2)(96s)^2
x=45265.7 m

that does not seem right at all
Repeat the calculation using the same equation with zero acceleration and you are done. Although there is gravitational attraction between the spacecraft and the astronaut, it should be considered negligible. Besides, the mass of the spacecraft is not given so you cannot calculate it.
 
  • #11
x= (1.118 m/s)(96 s) + 1/2 (0 m/s^2)(96 s)^2
x=107.328m
this is not correct.
 
  • #12
mandy9008 said:

The Attempt at a Solution


a. (91.3 kg)(0 m/s) + (12.0 kg)(0 m/s) = (91.3 kg)v1f + (12.0 kg)(8.50 m/s)
v1f=1.112 m/s
You made an error here. 91.3 kg is her total mass including suit and oxygen tank. If her oxygen tank is 12 kg, what's the mass of her and her suit?

Redo this to get the correct speed after she throws the tank.
 
  • #13
okay that makes sense. x=123.5 m Thank You
 

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