Consider a ray at the interface air and glass

  • Thread starter Gamma
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  • #1
Gamma
358
11
Consider a ray at the interface air and glass (n = 1.5). We know that incident angle i and refracted angle r are related by sin i = 1.5 sin r

Can we some how show the relationship between i and r is r = m i + c (straight line)?

If you look at the following data, it follows the Snell's law and r = 0.6 i + 1.

i r
10 7
20 13
30 19
40 25
50 31
 

Answers and Replies

  • #2
lightarrow
1,939
50
Consider a ray at the interface air and glass (n = 1.5). We know that incident angle i and refracted angle r are related by sin i = 1.5 sin r

Can we some how show the relationship between i and r is r = m i + c (straight line)?

If you look at the following data, it follows the Snell's law and r = 0.6 i + 1.

i r
10 7
20 13
30 19
40 25
50 31

Hoping this is not an homework, write r as function of i using Snell's law, then develop the functions sin and arcsin to the appropriate order (in radians), considering that 50° are less than 1 radian.
 

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