Considering Existing of a Partial Derivative

[makyol]

Homework Statement

[PLAIN]http://www.netbookolik.com/wp-content/uploads/2010/07/q1.png

Homework Equations

The Attempt at a Solution

I thought, in order to take derivative function must be cont. so it would be nice to check limf as (x,y) goes to (0, 0) but it did not seem to be a correct solution because appliying l'hopital gets harder and harder. If anyone can help me to solve this problem?

Thanks!

 

[HallsofIvy]

Don't use L'hopital. Instead, convert to polar coordinates. That way, the single variable, r, measures the distance to the origin.

Since x= r cos(\theta) and y= r sin(\theta),

\frac{x^5+ y^6}{(x^2+ y^2)^\alpha}= \frac{r^5cos^5(\theta)+ r^6sin^6(\theta)}{r^\alpha}
= \frac{r^5}{r^\alpha}(cos^5(\theta)+ rsin^6(\theta)}

As long as \alpha< 5, that will go to 0 as r goes to 0 no matter what \theta is and so the function will be continuous at (0, 0).

I would recommend you not worry about the continuity of the function itself but go ahead and take the derivatives with respect to x and y.