1. The problem statement, all variables and given/known data http://answers.yahoo.com/question/index?qid=20090812013110AAcrnFs 2. Relevant equations Equilibrium - Fx = Fcos(theta), Fy = Fsin(theta) 3. The attempt at a solution I've got the answer however it's different to the one posted the link above - isolated the top pipe and used equilibrium for the forces which were - normal force at C the weight W of the pipe and the force F exerted by the 2nd pipe. By doing this I found that F and C is 1387.344N. Then isolated the bottom pipe - forces present were - normal force at B and A, W and F exerted by 1st pipe. Did equilibrium and ended up with normal force at B = 4162.031N and normal force at A to be 3924N. Did I do something wrong or is there an issue with the answer on the link?