1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Contact forces

  1. Aug 7, 2011 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations
    Equilibrium - Fx = Fcos(theta), Fy = Fsin(theta)

    3. The attempt at a solution
    I've got the answer however it's different to the one posted the link above - isolated the top pipe and used equilibrium for the forces which were - normal force at C the weight W of the pipe and the force F exerted by the 2nd pipe. By doing this I found that F and C is 1387.344N. Then isolated the bottom pipe - forces present were - normal force at B and A, W and F exerted by 1st pipe. Did equilibrium and ended up with normal force at B = 4162.031N and normal force at A to be 3924N.
    Did I do something wrong or is there an issue with the answer on the link?
  2. jcsd
  3. Aug 8, 2011 #2


    User Avatar
    Homework Helper

    Not a very successful link ????
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook