- #1
jaci55555
- 29
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The graph of a continuous funtions (R -> R) is the subset G:={(x, f(x) | x element of R} is a subset of R^2. Prove that if f is continuous, then G is closed in R^2 (with euclidean metric).
I know that continuity preserves limits, so xn -> x in X means f(xn-> y in Y.
and for all A element of R^2 - G there exists r > 0 st B(a, r) subset of R^2 - G.I know that if R^2 - G is open then G is closed.
What is the connection between limits and the open ball B? I think that might be the way...
I know that continuity preserves limits, so xn -> x in X means f(xn-> y in Y.
and for all A element of R^2 - G there exists r > 0 st B(a, r) subset of R^2 - G.I know that if R^2 - G is open then G is closed.
What is the connection between limits and the open ball B? I think that might be the way...