Continuity of a complex function defined on the union of an open and closed set

ridethespiral
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Homework Statement



(i) Let U and V be open subsets of C with a function f defined on U \cup V suppose that both restrictions, f_u \mathrm{and} f_v are continuous. Show that f is continuous.

(ii) Illustrate by a specific example that this may not hold if one of the sets U, V is not open.

Homework Equations

The Attempt at a Solution



Now I'm pretty sure I can prove the first part. As, since f is continuous on U and V then there exists a \delta_1 and on U there will be a \delta_2 and then taking the minimum of these will put |f(z) - f(w)| < \epsilon for all epsilon. This works because U and V are open, as it ensures that for each w, there will be a delta disc such that z is in either U or V.

I'm pretty stumped as to an example for the second part. I think I get why it may not hold if U or V is not open, as there will not always be a delta disc around a point in a closed set which is completely contained in that set. But I can't think of a way to use this to arrive at an example.
 
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Hint: complex logarithm
 
Hmm, I'm not really sure how to use the logarithm. Is it because if you take the principal logarithm, there will be a discontinuity in the principal argument going from -π to π? So if you take the logarithm defined on \mathbb{C} \backslash {(-\pi, \pi]} then the set isn't open. Or perhaps, take U to be the upper half plane and V to be the lower, and the principal argument will be discontinuous? I'm not sure if this is making sense.

I'm confusing myself now. Our lecturer taught this module from a theoretical point of view but decides to make the exam this type of problem solving, which he hasn't really prepared us for. Thanks for any help.
 
Hint: Consider what can happen if U and V are disjoint and f is constant on U and constant on V.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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