- #1

Mystic998

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## Homework Statement

For reference, this is chapter 11, problem 12 of Rudin's Principals of Mathematical Analysis.

Suppose [tex] |f(x,y)| \leq 1 [/tex] if [tex] 0 \leq x \leq 1, 0 \leq y \leq 1 [/tex]; for fixed x, f(x,y) is a continuous function of y; for fixed y, f(x,y) is a continuous function of x.

Put [tex] g(x) = \int_{0}^1 {f(x,y) dy}, 0 \leq x \leq 1 [/tex].

Is g continuous?

## Homework Equations

N/A

## The Attempt at a Solution

To me it seems like this is obviously continuous since within an integral you're essentially working with a fixed y, so you can find some delta such that |f(x,y) - f(a,y)| is less than any positive epsilon, then the inequality you actually need follows easily. But it just seems way too easy.

Anyway, hope I didn't mangle the TeX. I'm not used to using it.

Just as a note, I'm referring to Lebesgue integration.

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