Continuous Time Fourier in LTI system

AI Thread Summary
The discussion focuses on solving a homework problem related to Continuous Time Fourier Transform in Linear Time-Invariant (LTI) systems. Participants express uncertainty about how to start the equation and whether to transform the input signal x(t). It is suggested that the definition of power can be useful, and that the power of a signal can also be derived from its Fourier transform. For Part A, it is emphasized that the Fourier transform of the signal is straightforward, while Part B involves using the transfer function to analyze how the system transforms the input sinusoids. Overall, understanding the relationship between the signal's spectrum and the system's transfer function is crucial for solving the problem.
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Homework Statement


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Homework Equations


Not sure


The Attempt at a Solution


No idea how to even begin.

I don't even know how to start this equation. My textbook has no examples of this type. Do I need to transform x(t)? If someone could simply steer me in the right direction I'm confident I can figure it out.
 
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beanus said:
I don't even know how to start this equation. My textbook has no examples of this type. Do I need to transform x(t)? If someone could simply steer me in the right direction I'm confident I can figure it out.
For Part A. You can solve this several different ways. If you don't know what to do, you should always resort to the definition of power. But in this case you should know that you can also find the power of a signal from its Fourier transform and this particular signal has a really simple Fourier transform. Normally I would just compute the power of the sinusoids from rms values but part A is leading into part B.

For Part B, the transfer function shows how sinusoids are transformed by the system. Your input is the sum of two sinusoids. Again, there is more than one way to do this one but the question is practically begging you to use |H| somehow. From part A you should have the spectrum of X and therefore its magnitude too.
 
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