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Continuous time signals - Causal signal given even part

  1. Sep 17, 2012 #1
    1. The problem statement, all variables and given/known data
    Suppose h(t) is a causal signal and has the even part h_e(t) given by:
    h_e(t)= t[u(t)-u(t-1)]+u(t-1) for t>0.

    Find h(t) for all t


    2. Relevant equations
    For an even function f(x), f(x) = f(-x)
    Also even functions can be expressed as x_e(t) = 1/2[x(t)+x(-t)]


    3. The attempt at a solution
    I'm unsure how to approach this problem.
    My assumption is that you have to find the odd part of the function and then sum the odd and the even components, since any function can be written as x(t)=x_e(t)+x_o(t) where x_e and x_o are even and odd functions.

    So far I've gotten that the plot of the even part looks like this:
    linear line with slope=1 from t=0-1 and then a straight line at 1 for t>1.
    EDIT: not 0 for t<0 since this is defined for t>0 and it's even so it must be symmetric about the y-axis?

    Since it says that this part is even and we know that that means h_e(t)=h_e(-t), does this means that it's symmetric about the y-axis and the question is asking me to find the odd function that essentially cancels out the negative part (making it causal) and thus amplifies the positive part?

    My biggest problem is understanding exactly what the question is asking me to do; if anyone could tell me if my attempts are right or how to proceed I would appreciate it! Thank you!
     
  2. jcsd
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