Contour integration using residue theorem (quick question)

markov4
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Homework Statement


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The Attempt at a Solution


So i have poles at: z=-1 of order 3, z=1 and z=2. For part i), no poles are located inside the contour, therefore the residue is 0. <--is that right to say, that since there are no poles inside the contour, the residue is zero?
 
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Yes, exactly!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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