kanki
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Are there 2 ways to convert CH_2 = CH_2 into a diol?
Can i use the alkaline KMnO4 and water at room temperature(mild oxidation) to convert it into a diol instead of this reaction:
CH_2 = CH_2 (g) + Br_2(l) \xrightarrow {room temperature} CH_2BrCH_2Br(l)
CH_2BrCH_2Br + 2 NaOH(aq) \xrightarrow {reflux} CH_2OHCH_2OH(l) + 2 NaBR(aq)
Where it requires to convert ethene to 1,2-dibromoethane first.
Can i use the alkaline KMnO4 and water at room temperature(mild oxidation) to convert it into a diol instead of this reaction:
CH_2 = CH_2 (g) + Br_2(l) \xrightarrow {room temperature} CH_2BrCH_2Br(l)
CH_2BrCH_2Br + 2 NaOH(aq) \xrightarrow {reflux} CH_2OHCH_2OH(l) + 2 NaBR(aq)
Where it requires to convert ethene to 1,2-dibromoethane first.