- #1
City88
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Homework Statement
I'm trying to solve a double integral of a function which is bounded by the ellipse:
[tex]\frac{(x-2)^2}{16}} + \frac{(y-4)^2}{36}}[/tex] = 1
And I can't figure out how to write this in polar coordinate form, and also what my bounds for theta and radius would be.
Homework Equations
I know that for a circle, the polar coordinates are
x=rcos(theta) and y=rsin(theta)
theta going from 0 to 2pi, and r going from o to a(being the radius)
The Attempt at a Solution
Well I know that an ellipse is not a circle! so I can't apply this formula without doing some tweaking. Can anyone help with this "tweaking"?
I have started by thinking it would be something like..
x=rcos(theta) + 2
y=rsin(theta) + 4
Because the ellipse is not in the center, but I can't figure out what else to do...