Converting mks energy density to cgs

AI Thread Summary
The discussion focuses on converting the energy density of electric and magnetic fields from SI units to the Gaussian system. The initial equation provided for energy density includes constants epsilon and mu, which are not present in the cgs system. Participants highlight that in cgs, the definitions of electric charge and magnetic permeability change, affecting how energy density is expressed. References to textbooks and online resources are suggested for further clarification on the differences in unit systems. The conversation emphasizes the complexities involved in this conversion, particularly regarding the treatment of constants.
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Homework Statement



In the SI system, the energy density of the electric and magnetic fields is:

<br /> u = \frac {\epsilon_{0} E^{2}}{2} + \frac{B^{2}}{2 \mu_{0}}<br />

From the equation above, derive an exact expression for the energy density U in the Gaussian system of units.


The Attempt at a Solution



Obviously the energy densities must be proportional to the squares of the intensities. So, I can start with

U_{tot} = E^{2} + B^{2}

I know that cgs eliminates the need for epsilon and mu, but I haven't a clue as to how to start from that one equation. Previously in the assignment, my instructor mentions that in Coulomb's law, \epsilon_{0} has been eliminated by redefining the electric charge in the Coulomb law (\frac{q_{1} q_{2}}{4 \pi \epsilon_{0}} \rightarrow q_{1} q_{2}) and \mu_{0} has been eliminated by using the speed of light: \mu_{0} \rightarrow \frac{1}{c^{2} \epsilon_{0}}.

However I haven't a clue as to how to proceed with this information. Any hints would be great! Thanks in advance.

Stephen
 
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There's an epsilon and a mu in the cgs system as well. There's something linked with #-s and 4\pi-s that differs. On a second thought, since i haven't used cgs since college, go and check the 3-rd and 2-nd editions of JD Jackson's electrodynamics book to see everything exactly.
 
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syang9 said:

Homework Statement



In the SI system, the energy density of the electric and magnetic fields is:

<br /> u = \frac {\Epsilon_{0} E^{2}}{2} + \frac{B^{2}}{2 \mu_{0}}<br />

From the equation above, derive an exact expression for the energy density U in the Gaussian system of units. Stephen
Hopefully you found this one already:

http://en.wikipedia.org/wiki/Electromagnetic_stress-energy_tensor

If \frac {1}{4 \pi \epsilon_{0}} = 1, then \epsilon_{0} = \frac {1}{4 \pi}, and likewise for magnetic field.

Although, often epsilon is not what it seems in cgs. It really depends on whether you are looking at emu or esu. I recommend this document, which gives you a little taste of the complications of calling 4 \pi = 1, or \epsilon_{0} = 1, despite it's readability difficulties:

http://www.scribd.com/doc/8520766/Cgs-Electricity-and-Magnetism
 
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