Converting square root to perfect square

AI Thread Summary
The discussion revolves around a method for converting the expression √(36 + x²) into a perfect square by substituting x with 3(t - 1/t). The user questions the rationale behind choosing this specific substitution and whether there is a rule governing it. They note that while they understand the overall goal of solving the equation C(x) = [(9-x) + 1.25√(x² + 36)], the substitution process confuses them. The conversation suggests that there may not be a strict rule for this substitution, indicating a more intuitive or exploratory approach to the problem. Ultimately, the focus is on understanding the transformation of the expression into a more manageable form.
cstvlr
Messages
12
Reaction score
0

Homework Statement



Hi,

I have a problem in my book in which they use a method of making sqrt( 36 + x^2 ) a perfect square by simply making x = 3( t - 1/t ) and then we get 9( t + 1/t )^2 by substituting back into sqrt(36 + x^2). My question is that why did the chose 3( t - 1/t ), is there a rule?

thanks in advance.
 
Physics news on Phys.org
What were they trying to do with the expression √(36+x2) ? For example, if they were trying to integrate, you could have made a simple trig substitution instead of trying to think of some odd set of functions to string together.
 
no its in an equation form,

C(x) = [(9-x) + 1.25sqrt( x^2 + 36 )], where C(x) is a function.

and they're trying to solve for x, so they used the method above, and I know how to solve it, but I lost it when they used let x = 3( t - 1/t )
 
cstvlr said:
no its in an equation form,

C(x) = [(9-x) + 1.25sqrt( x^2 + 36 )], where C(x) is a function.

and they're trying to solve for x, so they used the method above, and I know how to solve it, but I lost it when they used let x = 3( t - 1/t )

x = 3( t - 1/t ) ⇒ x2 = 9( t - 1/t )2

∴√(36+x2)=√(36+9(t- 1/t)2), how does that turn into an expression like √(a+b)2?

I do not think there rule per se for using that substitution though.
 
Fair enough, thanks anyway.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top