Coordinates and change of base

robertjford80
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Homework Statement


Screenshot2012-05-12at100357PM.png




The Attempt at a Solution



I don't understand where 2v1 + 3v2
and
4v1 - 3v2

came from.
 
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I see that the vectors are raised to T which I'm pretty sure means they're transposed but that still doesn't get me anywhere.
 
Where's Figure 3.29a? You should post the whole example to help us get a clearer picture of the problem.
 
You are solving the equations
x= \begin{bmatrix}11 \\ 7\end{bmatrix}= a\begin{bmatrix}1 \\ 2\end{bmatrix}+ b\begin{bmatrix}3 \\ 1\end{bmatrix}
which is the same as the two equations a+ 3b= 11 and 2a+ b= 7. Can you solve for a and b?
And
y= \begin{bmatrix}-5 \\ 5\end{bmatrix}= c\begin{bmatrix}1 \\ 2\end{bmatrix}+ d\begin{bmatrix}3 \\ 1\end{bmatrix}
which is the same as the two equations c+ 3d= -5 and 2c+ d= 5. Can you solve for a and b?
 
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ok, thanks, I got it now.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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