Coriolis expression - Question about sign

Curious2013
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Homework Statement



Dear all

I have a question concerning the Coriolis acceleration expression. I learned it as Ac = -2ω x v, where ω is the vector which indicates the rotation axis direction of Earth and v the velocity of a body that I want to check the Coriolis effect on.

My question: where the minus sign comes from? As far as I understand, it depends on what reference frame I use (inertial or non inertial - the minus comes from the latter, like the Earth, in my conception). Am I correct?

Thanks in advance!

Homework Equations





The Attempt at a Solution

 
Welcome to PF!

Hi Curious2013! Welcome to PF! :smile:
Curious2013 said:
I have a question concerning the Coriolis acceleration expression. I learned it as Ac = -2ω x v, where ω is the vector which indicates the rotation axis direction of Earth and v the velocity of a body that I want to check the Coriolis effect on.

My question: where the minus sign comes from? As far as I understand, it depends on what reference frame I use (inertial or non inertial - the minus comes from the latter, like the Earth, in my conception). Am I correct?

There's no Coriolis force in an inertial frame. :wink:

(same as centrifugal force)
 
The sign is solely due to the choice of coordinates. Here's a site that derives it as positive:

http://www.nws.noaa.gov/om/wind/deriv.shtml
 
Last edited by a moderator:
TheEtherWind said:
Here's a site that derives it as positive:

no, it derives it as negative

Coriolis force exists only in the Earth's frame (the rotating frame),

so in that frame (d2R/dt2)Earth is on one side of the equation, and everything else on the other side …

the Coriolis force then does have a negative sign :wink:
 

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