- #1
Punkyc7
- 420
- 0
Let H and K be Subgroups
show Ha[itex]\cap[/itex]Ka = (H[itex]\cap[/itex]K)a for all a [itex]\in[/itex]G
pf
Let x[itex]\in[/itex]Ha[itex]\cap[/itex]Ka
Then x[itex]\in[/itex]Ha and x[itex]\in[/itex]Ka
Can I just say that x [itex]\in[/itex](H[itex]\cap[/itex]K)a ? Or am I missing something.
show Ha[itex]\cap[/itex]Ka = (H[itex]\cap[/itex]K)a for all a [itex]\in[/itex]G
pf
Let x[itex]\in[/itex]Ha[itex]\cap[/itex]Ka
Then x[itex]\in[/itex]Ha and x[itex]\in[/itex]Ka
Can I just say that x [itex]\in[/itex](H[itex]\cap[/itex]K)a ? Or am I missing something.