Coulomb ( Electric force and charge )

AI Thread Summary
The total charge of the radon nucleus is calculated to be 1.38 x 10^-17 C, based on its 86 electrons. The electric field magnitude at a distance of 9.6 x 10^-10 m from the nucleus is +1.34 x 10^11 V/m. The force on an electron at that distance is computed using the formula F = qE, resulting in a value of 2.10 x 10^-8 N. There is confusion regarding the sign of the charge used in the calculation, as the computer indicated an incorrect answer. Clarification on the charge's sign and its impact on the force calculation is needed.
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Homework Statement



1. [1pt]
What is the total charge of the radon nucleus? (The neutral radon atom has 86 electrons.)

1.38 * 10^-17 C


2. [1pt]
What is the magnitude of its electric field at a distance of 9.6 x10-10 m from the nucleus?

+1.34 * 10^11 V/m

3. [1pt]
What is the magnitude of the force on an electron at that distance?





Homework Equations



F=qE

q = +/- 1.60 * 10^-19 C

The Attempt at a Solution




F = (- 1.60*10^-19C)(1.34*10^11 V/m )
= 2.10*10^-8 N

I tried to use + and -ve C to get my answer, but the computer told me I got the wrong answer. Is there something that I'm missing?

Thanks
 
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even i got same answer
 

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