Coulomb's Law Problem: Net Electrostatic Force on Particle 3 at 5.5 cm Distance

  • Thread starter Thread starter noname1
  • Start date Start date
  • Tags Tags
    Law
AI Thread Summary
The discussion centers on calculating the net electrostatic force on particle 3, given specific charges and distances. The charges involved are q1 = -q2 = 233 nC and q3 = -q4 = 201 nC, with a distance of 5.5 cm. Participants emphasize the importance of considering the negative charges, which influence the direction of the forces as attractive or repulsive. A suggestion is made to visually represent the forces acting on particle 3 with arrows and to break them into components for accurate calculations. Understanding the signs of the charges is crucial for determining the correct net force components.
noname1
Messages
131
Reaction score
0
In the figure atatched, the particles have charges q1 = -q2 = 233 nC and q3 = -q4 = 201 nC, and distance a = 5.5 cm.


For the following questions, take right to be the +x direction and up to be the +y direction.

(a) What is the x component of the net electrostatic force on particle 3?

(b) What is the y component of the net electrostatic force on particle 3?

I have all of my work attached and i can't figure out where i have my error
 

Attachments

  • scan0003.jpg
    scan0003.jpg
    53.3 KB · Views: 516
Last edited:
Physics news on Phys.org
Your error is in not taking into account the negative charges, namely q2 = -233 nC and q4 = -201 nC. I suggest that you draw three arrows on particle 3, one for each force acting on that charge. Pay attention to the signs of the charges because they decide which forces are attractive and which are repulsive. Break the arrows into components after you have drawn them in the figure.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top