Covariant Tensor first order, and antisymmetric second order

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SUMMARY

The discussion focuses on proving that the expression T_{ik} = ∂V_i/∂x^k - ∂V_k/∂x^i represents a second-order covariant antisymmetric tensor derived from a first-order covariant tensor V. The definition of a first-order covariant tensor is provided, emphasizing its transformation properties under coordinate changes. The solution approach involves applying the chain rule to the transformed version of T_{ik} to demonstrate its antisymmetry.

PREREQUISITES
  • Understanding of tensor calculus and its notation.
  • Familiarity with coordinate transformations in tensor analysis.
  • Knowledge of the chain rule in calculus.
  • Basic concepts of covariant and contravariant tensors.
NEXT STEPS
  • Study the properties of covariant tensors in detail.
  • Learn about antisymmetric tensors and their applications.
  • Explore coordinate transformations and their effects on tensor components.
  • Practice using the chain rule in the context of tensor calculus.
USEFUL FOR

Students and researchers in mathematics and physics, particularly those focusing on tensor analysis, differential geometry, and theoretical physics.

Telemachus
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Hi there. This is my first time working with tensors, so I have to break the ice I think. I have this exercise, which I don't know how to solve, which says:

If [tex]V=V_1...V_n[/tex] is a first order covariant tensor, prove that:
[tex]T_{ik}=\frac{\partial V_i}{\partial x^k}-\frac{\partial V_k}{\partial x^i}[/tex]

Is a second order covariant antisymmetric tensor.

Now, in my notes I have this definitions:
A vector field V is a first order covariant tensor, if under a change of coordinates from [tex]x[/tex] to [tex]\overline x[/tex] it's components are:
[tex]\overline {V}=\frac{\partial x^r}{\partial \overline {x}^i}V_r[/tex]

I think I should use this, but as I said, I'm starting with this, and I don't know how to work this out.

Any help will be appreciated.
 
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Hi Telemachus! :smile:
Telemachus said:
[tex]T_{ik}=\frac{\partial V_i}{\partial x^k}-\frac{\partial V_k}{\partial x^i}[/tex]

Write out the barred version of that equation, then use the chain rule to compare one with the other. :wink:
 
Thank you Tim.
 

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