Creating an Equation for f(t) from the Last Waveform in the Picture

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The discussion focuses on deriving an equation for a full-wave rectified sine waveform depicted in a referenced image. Participants clarify that the waveform is represented as the absolute value of a sine function, specifically f(t) = A|sin(2πt/T)|. There is also mention of defining the function piecewise for different intervals, ensuring it is zero where the waveform is flat. Corrections are made regarding the period of the sine function, emphasizing that the correct period is 2T. Overall, the key takeaway is the formulation of the full-wave rectified sine wave equation and its piecewise representation.
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ACLerok said:
http://www.rfcafe.com/references/electrical/images/period5.gif

For the last waveform in the picture above. How would i go about writing an equation for f(t)?

Thanks in advance

As an absolute value of something, or as a piecewise definition for each of the intervals that has a continuous derivative.
 
I'm sorry i do not follow. I understand if it was just a ramp function it would just be (Vm/T) t but i still don't know
 
ACLerok said:
I'm sorry i do not follow. I understand if it was just a ramp function it would just be (Vm/T) t but i still don't know

The last waveform is called a Full-wave rectified sine. It is a sine function with all the negative regions flipped to positive. It is the absolute value of the sine function

f(x) = \left| {A\sin 2\pi \frac{t}{T}} \right| = A\left| {\sin 2\pi \frac{t}{T}} \right|

or you could write separate functions for the separate intervals with alternating plus and minus signs in front of the sine function.
 
i see.. so am i correct to say that the equation for f(x) for the third waveform would be Asin(4pi/T)?
 
ACLerok said:
i see.. so am i correct to say that the equation for f(x) for the third waveform would be Asin(4pi/T)?

No. For one thing you need a variable, t, in the argument of the sine function (T is a constant) and you need to define the function to be zero in the intervals where the waveform is zero. One way to do that would be to take 1/2 times your second waveform and add A/2 so that the square wave is between 0 and A; then use that in place of the A in the sine function you have.
 
for the full rectified sine wave, the equation for f(t) from 0 to T/2. can it not have a sin in the equation maybe something like A(1-t^2)? (i know that's incorrect)
 
anyone? :(
 
ACLerok said:
for the full rectified sine wave, the equation for f(t) from 0 to T/2. can it not have a sin in the equation maybe something like A(1-t^2)? (i know that's incorrect)

I'm not sure what you are asking. For the full-wave rectified sine the function is a sine function from 0 to T

f(x) = A\sin \pi \frac{t}{T}}

Between T and 2T it is

f(x) = -A\sin \pi \frac{t}{T}}

There is no 1-t^2 involved
 
  • #10
OlderDan said:
The last waveform is called a Full-wave rectified sine. It is a sine function with all the negative regions flipped to positive. It is the absolute value of the sine function

f(x) = \left| {A\sin 2\pi \frac{t}{T}} \right| = A\left| {\sin 2\pi \frac{t}{T}} \right|

or you could write separate functions for the separate intervals with alternating plus and minus signs in front of the sine function.

CORRECTION!

Sorry, I misinterpreted the T as being the period of the sine function. In fact 2T is the period in the figure. This should have been

f(x) = \left| {A\sin \pi \frac{t}{T}} \right| = A\left| {\sin \pi \frac{t}{T}} \right|
 
  • #11
ACLerok said:
i see.. so am i correct to say that the equation for f(x) for the third waveform would be Asin(4pi/T)?

From 0 to T/2 or from nT to (n+1/2)T this should be

f(x) = {A\sin 2\pi \frac{t}{T}}

From T/2 to T or from (n+1/2)T to (n+1)T f(x) is zero.
 
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