Critical Exponents in the 1D Ising Model

MisterX
Messages
758
Reaction score
71

Homework Statement


Obtain the critical exponents for specific heat, susceptibility, and the order parameter (magnetization).

Homework Equations


$$A = -k_B T N \ln \left[e^{\beta J} \cosh (\beta h) +\sqrt{ e^{2\beta J}\sinh^2 \beta h + e^{-2\beta J} }\right]$$
$$\left<m \right> \propto \frac{\partial A}{\partial h} \to \frac{\sinh (\beta h)}{\sqrt{\sinh ^2(\beta h)+e^{-4 \beta J}}}$$
$$\chi_T = \left(\frac {\partial \left<m \right>}{\partial h} \right)_T = \frac{\beta \cosh (\beta h)}{\sqrt{\sinh ^2(\beta h)+e^{-4 \beta J}}}-\frac{\beta \sinh ^2(\beta h) \cosh (\beta h)}{\left(\sinh ^2(\beta h)+e^{-4 \beta J}\right)^{3/2}} $$

The Attempt at a Solution


I can understand how to derive these various expressions above but I don't know how to determine the critical exponent using them. The "base" for this exponent shold be ##e^{-\beta J}##.

So I need to show for example ## \chi \sim \left( e^{-\beta J}\right)^p ## as ##\beta \to 0##. I have tried using the formal definition of asymptotic and found exponent 0 for magnetization, but I'm not sure this is correct. Also it appears for the susceptibility there is no value of p for which the susceptibility will be asymptotic. So maybe they critical exponents come from a looser definition then asymptoticity?
 
Physics news on Phys.org
Sorry that should be ##\beta\to \infty##
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top