Critical numbers of this derivative

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opticaltempest
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I have the function \[y = \sqrt x - 4\ln (x)\]

I find the derivative to be \[y' = \frac{{\sqrt x - 8}}{{2x}}\]

When finding the critical numbers of y' I look for where the derivative
is equal to zero or where the derivative is undefined. So where y' is
equal to zero is when x=64. y' is undefined when x=0, but when x=0
the original function is also undefined. Since x=0 makes the original
function undefined can I exclude it from my critical points? I am thinking
I am able to since x=0 isn't even in the domain of y.

Thanks
 
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Yes, that is correct. By the way, the phrase "critical numbers of y' " is not correct. What you have found are the critical numbers of y itself, not its derivative.
 
Thanks HallsofIvy :smile:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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