Critical Points of Log Function

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Homework Statement



http://i.minus.com/jCH20SF290QIb.png

Homework Equations



Critical point: when the derivative = 0 or the derivative fails to exist.

The Attempt at a Solution



I got x = 0 and x = e as critical points.

When x = e, the function becomes 0 / e, which = 0. Therefore, e is a critical point of f.

When x = 0, the function becomes 1/0, which = ∞. The derivative of ∞ does not exist, so wouldn't x = 0 be a critical point?

The answer key disagrees; the only critical point the key provides is x = e.
 
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the key to this problem is in the first line: "for all x > 0". Log(x) is not defined for any x ≤ 0
 
Actually, it's the fact that f is defined only for x>0 that matters. If the problem said f(x) = (ln x)/x for all x>10, f would have no critical points.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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