Critical Points of Log Function

Qube
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Homework Statement



http://i.minus.com/jCH20SF290QIb.png

Homework Equations



Critical point: when the derivative = 0 or the derivative fails to exist.

The Attempt at a Solution



I got x = 0 and x = e as critical points.

When x = e, the function becomes 0 / e, which = 0. Therefore, e is a critical point of f.

When x = 0, the function becomes 1/0, which = ∞. The derivative of ∞ does not exist, so wouldn't x = 0 be a critical point?

The answer key disagrees; the only critical point the key provides is x = e.
 
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the key to this problem is in the first line: "for all x > 0". Log(x) is not defined for any x ≤ 0
 
Actually, it's the fact that f is defined only for x>0 that matters. If the problem said f(x) = (ln x)/x for all x>10, f would have no critical points.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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