Curl of Z-unit vector in spherical coordinates

SalcinNossle
Messages
5
Reaction score
0

Homework Statement



There is a sphere of magnetic material in a uniform magnetic field \vec H_0=H_0\vec a_z,
and after some calculations I got the magnetic moment vector \vec M_0=M_0\vec a_z, where M_0 is something that isn't important to my question. I am unsure if this magnetic moment vector is correct, as I am running into trouble when I try to figure out the equivalent volume current on the sphere:

\vec J_{mv}=\nabla\times\vec M_0,

Is it possible for me to take the curl of a Z-vector, in spherical coordinate system?

Edit: I made a mistake in the title, I meant to take curl of Z, not cross with unit normal of surface of the sphere. Sorry!
 
Last edited:
Physics news on Phys.org
Hello. Are you asking if it is possible to take the curl of the unit vector ##\hat{a}_z## in spherical coordinates?

If so, the answer is yes. You can do it as an academic exercise, but that would not be the easiest way to get the answer. Note that ##\hat{a}_z## is a constant vector - it is the same vector at all points of space. So, you are taking the curl of a constant vector and the result should be immediate. Or, you can easily see what the result is by taking the curl in Cartesian coordinates rather than spherical coordinates.

If you do want to take the curl in spherical coordinates, then you would want to express ##\hat{a}_z## in terms of the spherical coordinate unit vectors ##\hat{a}_r##, ##\hat{a}_{\theta}##, and (if necessary) ##\hat{a}_{\phi}##.
 
Thank you! I did take the curl in spherical coordinates for practice, and I got zero! I think it' correct.
 
OK. That's good.
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top