Current & Charge Homework: Calculate Electrons/Charge

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To calculate the number of electrons passing a point in a wire with a 5A current over 10 minutes, the total charge can be determined using the formula Q = I × t, where Q is charge, I is current, and t is time. For the electric beam with a current of 1.2mA, the charge flowing each minute can be calculated similarly. The number of electrons can then be found by dividing the total charge by the charge of a single electron, approximately 1.6 x 10^-19 coulombs. These calculations are essential for understanding current flow in electrical circuits and experiments. Accurate calculations are crucial for successful outcomes in physics experiments.
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Homework Statement




Hi, Can you please help with the following:
1. Calculate the number of electrons passing a point in the wire in 10min when the current is 5A

2. In an electric beam experiment the beam current is 1.2mA. Calculate
a. the charge flowing along the beam each minute
b.the number of electrons that pass along the beam each minute

Homework Equations


1 c= 1.6x10^19



The Attempt at a Solution

 
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Hi, Can you please help with the following:
1. Calculate the number of electrons passing a point in the wire in 10min when the current is 5A

2. In an electric beam experiment the beam current is 1.2mA. Calculate
a. the charge flowing along the beam each minute
b.the number of electrons that pass along the beam each minute
2. Homework Equations
1 c= 1.6x10^19
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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