Find Current I1 in 7.5 Ω Resistor with Kirchhoff's Rule

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To find the current I1 through a 7.5 Ω resistor using Kirchhoff's Rule, the user attempted to calculate equivalent resistances and break down the total current into I1 and I2. Despite following the correct approach, they did not arrive at the expected answer of 0.65 A. Other participants confirmed that the method used was valid and suggested reviewing the calculations for potential errors. Sharing the detailed working steps was recommended for further assistance. Accurate application of Kirchhoff's rules is essential for solving such circuit problems effectively.
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Homework Statement


In the circuit below: (a) Find the current I1 that passes through the 7.5 Ω resistor.



Homework Equations



Kirchhoff's Rule--Loops

The Attempt at a Solution


This was a problem in my textbook. The answer is .65 A, but I don't understand how to get that. I tried Kirchhoff's rule by finding equivalent R between A & B and Then finding equivalent R between A & C then finding I, Then breaking I into I1 and I2 (according to the parallel resistances between A & B)

However, I still didn't get the answer, .65 A. Was my approach correct, or is there another way? Thank you.
 

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Your plan of how to solve it is OK, and when I did it that way I got 0.65A.

If you can't find your mistake, show your working, then somebody can check through it.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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