Current in 3Phase, 4Wire System w/ 8 Loads

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In a 3-phase, 4-wire system with a voltage of 0.38/0.22 kV and eight loads of 2 kVA each, the current in the neutral line can be calculated based on the load distribution. With three loads on phases A and B and two loads on phase C, the asymmetry leads to a neutral current. The neutral current is approximately 10 A, derived from dividing the total load of 2 kVA by the phase voltage of 0.22 kV. This calculation accounts for the vector nature of the loads, ensuring that the neutral carries the imbalance. Understanding these principles is crucial for effective electrical system design and load management.
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how much is the current in a neutral line of 3phase and 4 wire system with voltage of 0.38/0.22kV. where we have 8 loads which each load is 2 kVA. 3 loads connected to each phase of A and B and 2 loads connected to phase c.
 
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Sounds like a homework problem. Use the template and show some attempt to solve it yourself and ask questions about whatever you are stuck on.
 
you will have current that neutralise any asymmetry in your load - in your case that is 1 load on A and B each. which is equal to 1 load on C if you think about vectors (absolute value).

you will have 2 (kVA) / 0,22 (kV) = cca 10 A in neutral.
 

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