Current induced in loop - treat like a solenoid?

AI Thread Summary
A long straight wire carrying a constant 10A current generates a magnetic field affecting a nearby circular loop with a diameter of 1 m, positioned 0.75 m away. The magnetic field at the loop is directed out of the screen, leading to a counterclockwise induced current in the loop. The magnetic field is calculated using the formula B = μi / 2πr, resulting in a value of approximately 0.213 T. By treating the loop similarly to a solenoid, the induced current is determined to be around 2.71 A. The discussion highlights the complexities of assuming uniform magnetic fields in such configurations.
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Homework Statement



A long straight wire lies below to a circuluar loop of wire. The straight wire is carrying a constant 10A current to the right. What is the magnitude and direction of the current in the circular loop, if its diameter is 1 m and its center is 0.75m away from the wire


Homework Equations



B = u i / 2pir

B = u i N for solenoid


The Attempt at a Solution



B = ui/2pir
since current in wire is traveling right and the loop is above the wire, the magnetic field on the loop is going to be coming out of the screen, I'm going to assume that the magnetic field is uniform, using the distance from the center as the radius, even though.. that is probably a bad assumption?

so the current will travel counterclockwise

can't figure out how to find the magnitude though! should i be treating it like a solenoid, and plug in the magnetic field to get a current?
 
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B = ui/2pir = (4pix10^-7)(10)/2pi(0.75)= 0.213 TB = uiN N = 4pix0.75/2pi = 0.47 turnsI = B/uN= (0.213 T)/(4pix10^-7 x 0.47 turns)= 2.71 A
 
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