sophiecentaur
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Baluncore said:The inside of the outer conductor is a excellent conductor. That makes it a good EM mirror. Any magnetic field incident with the inside surface will induce a perpendicular longitudinal current that will create a reverse magnetic field to cancel the incident field. Those two fields cancel everywhere outside the inner surface of the outer conductor.
You are hypothesising that the magnetic field inside the transmission line is caused by a current flowing “in” the conductor. But that current was induced in that mirror surface by an incident internal magnetic field. You are forgetting that the EM field within a coaxial cable is constrained to the dielectric by the surface currents on the reflective “walls”.
When you connect a transmission line to a signal you are connecting the dielectrics and the conductive reflective walls. You do that by making sure that longitudinal surface currents and electric field between the surfaces will not be interrupted at the interface.
Hypothesising your own personal theory is a most inefficient way of approaching the subject. It wastes your time and the time of those who answer your questions. You question the paradigm by proposing a simpler model of reality that does not fit the paradigm. You then call for someone to say why your poorly specified model is wrong. That requires they understand your immature model, which is different to their reality. It is better to read and understand the physics than to learn in an ever changing feedback loop where communications in the English language gets two chances to be misunderstood per cycle.
I'm not sure what you're implying here. Are you suggesting that the internal B field is eliminated due to reflections? (perhaps not) There is a B field inside the 'cavity, which is circumferential (Transverse). There are a load of links that show how this can be calculated using Ampere's Law and it is finite at the inner surface of the outer conductor and at the outer surface of the inner conductor. This link shows it in detail but there is a graph showing the results of the calculations and the way the field varies with the radius. It shows that the external field is zero and that it exists throughout the conductors (depending on the resistivity)
If tim looks at the link, above, he will see the actual situation and will not need to try an alternative personal approach.