Current Rating of an AC Generator

AI Thread Summary
The current rating of an AC generator is determined using the formula kW = V * I * PF * sqrt(3), where PF represents the power factor. In three-phase systems, the inclusion of sqrt(3) accounts for the relationship between line and phase voltages. For a generator rated at 875 kVA with a power factor of 0.8, the corresponding kW output is indeed 700 kW. To find the current rating, the equation can be rearranged to solve for I using the known voltage and power factor. Understanding these formulas is crucial for accurately calculating the performance of AC generators.
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Hello,

I'm a bit confused on the term current rating in an ac generator. Is it the one in that I can get in the formula:
kW= V*I*PF*sqrt(3) ? or the one in kW= V*I*sqrt(3)? The problem is the data that I have is V, PF, kVA only. I can compute the kW using those data but I'm abit confused on those formulas.

Also, I've read in some books that there are times that if the generator is 3 phase, the formula has a sqrt(3) why is that so?

Thanks!
 
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It's the first equation. Naturally that means the power depends on the power factor of the load.
 
russ_watters said:
It's the first equation. Naturally that means the power depends on the power factor of the load.

So for example I have a 875kVA and a .8 power factor, my kW will then be 700 kW right?

According to the first equation, If I have a volts of 2400, it will be 700 kW = 2400 * I * .8 *sqrt(3)
That way I can have the current rating?
 
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