Currents and magnetic fields in a coil

AI Thread Summary
To calculate the magnetic field strength of the horseshoe magnet affecting the coil, start by equating the magnetic force on the coil to the horizontal component of its weight. The mass of the coil is 20 grams, and the current flowing through it is 2.0 amps, with the coil positioned at a 30-degree angle to the vertical. The key formulas to use include F = BIL sin(θ) and the weight component F = mg, where g is the acceleration due to gravity. It's important to consider the forces acting on the coil, including the magnetic force and the tension or support keeping the coil in position. This problem involves understanding the balance of forces and torques, typical in statics problems.
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Please help me if you can...

question: Use the following quantities to calculate the magnetic field strength of the horseshoe magnet.

Mass of coil: 20 grams
current in coil: 2.0 amps
length of bottom of coil: 10cm
angle coil makes with vertical: 30 degrees

Hint: Equate magnetic force on bottom of coil to the horizontal componen of the coils weight.

The question also adds that there are at least 3 assuptions made in answering this question.

I've got a diagram
http://i122.photobucket.com/albums/o272/science_f/0000000000000coilandmagnet.jpg

I don't know where to start in the calculating process:confused: Can someone please help me with the starting point and i'll try and progress from there...this is the first time I've seen a problem like this:blushing:
 
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these are the formulas I know:
B=F/IL
F=BIL sin @
B=kI/r
B=2(pi)knI

Where k is Amperes constant (2x10^-7NA^-2), L is the length of wire, I is the current, r is the radius of the wire (but in some cases the distance between wires), and F is the force.

Here's another diagram with brainstorming but I'm not sure if i grasp the concept of this...I think it is all wrong:cry:

http://i122.photobucket.com/albums/o272/science_f/000000000000h.jpg

I actually think that there isn't enough information to do the problem unless it is as simple as:
F=mg=20x9.8=196
B=F/IL
B= 196/2.0x10
B=9.8
But i don't think that can be right
 
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-_-' said:
Please help me if you can...

question: Use the following quantities to calculate the magnetic field strength of the horseshoe magnet.

Mass of coil: 20 grams
current in coil: 2.0 amps
length of bottom of coil: 10cm
angle coil makes with vertical: 30 degrees

Hint: Equate magnetic force on bottom of coil to the horizontal componen of the coils weight.

The question also adds that there are at least 3 assuptions made in answering this question.

I've got a diagram
http://i122.photobucket.com/albums/o272/science_f/0000000000000coilandmagnet.jpg

I don't know where to start in the calculating process:confused: Can someone please help me with the starting point and i'll try and progress from there...this is the first time I've seen a problem like this:blushing:
What is a horizontal component of weight? I don't think they really mean that. The magnet will exert a force on the lower branch of the coil. You need to think about the direction of the magnetic force. You also need to think about what is keeping the coil in position. There has to be something besides the magnetic force. Something has to be keeping the top of the coil in position. What will be the direction and magnitude of the force on the top of the coil? It will help if you rotate the image so that the magnet is in the plane of the page, and the loop is perpendicular to the page so that the 30 degree tilt can be seen.
 
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thanks for that every little bit of info helps
 
-_-' said:
thanks for that every little bit of info helps
Hopefully you will recognize that this becomes a statics problem where one of the forces involved is a magnetic force. Think forces and torques and all the usual things you use for statics problems.
 
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