Curvilinear Motion: Rectangular Components

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The discussion focuses on calculating the magnitude of velocity at t=4.00s for a given position function in curvilinear motion. The user derived the velocity vector by taking the first derivative of the position equation, resulting in a velocity vector of approximately [(8.96)i + (2.91)j - (7)k] ft/s. The calculated magnitude of this velocity vector is 11.74 ft/s. However, the user notes that the result cannot be accurate to four significant digits. The conversation emphasizes the importance of precision in calculations related to curvilinear motion.
aaronfue
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Homework Statement



What is the magnitude of the velocity at t=4.00s?

I would like to see if my approach and answer is correct.

Homework Equations



Position: r = {-30cos(\frac{\pi}{10}t) i + 30sin(\frac{\pi}{10}t) j - (7t) k} ft


The Attempt at a Solution



I took the first derivative to get the velocity and my equation came out to be:

r' = {3\pisin(\frac{\pi}{10}t) i + 3\picos(\frac{\pi}{10}t) j - (7) k} \frac{ft}{s}

And after plugging in t=4, my velocity vector equation was: [(8.96)i + (2.91)j - (7)k] \frac{ft}{s}

Then my velocity magnitude was: 11.74 \frac{ft}{s}
 
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It is OK, but the result can not be accurate to four significant digits.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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