Cut-off frequencies, Quality for a given Transfer Function

AI Thread Summary
The discussion revolves around analyzing the transfer function H(s)=10s/(s^2+300s+10^6) of an RLC band pass filter to find the center frequency, half power frequencies, and quality factor Q. Initially, confusion arises due to the differing values of (R/L) in the numerator and denominator, leading to uncertainty about whether it represents an active band pass filter. The participant seeks guidance on how to approach the problem, considering methods to determine cut-off frequencies. Ultimately, they realize that by multiplying the transfer function by (30/30), it can be reformulated to match the ideal band pass function format, allowing for the extraction of the required parameters. This insight resolves their initial confusion and provides a clear path forward.
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Homework Statement



Given the network transfer function

H(s)=10s/(s^2+300s+10^6)

Find the center frequency, lower and upper half power frequencies and the quality factor Q.

Homework Equations



Beta=R/L

(omega naught)^2=1/(LC)

BW=hi-lo=R/L

H(s)=(R/L)s/(s^2+(R/L)s+1/(LC))

The Attempt at a Solution



Well I am truly stumped. Our prof has given us an equation for the transfer function of RLC band pass filter and the equation in the problem nearly fits the format (located above), however the value for (R/L) differs in the numerator and denominator suggesting it is an active band pass filter. However our prof has not mentioned anything about active band pass filters yet in class (I was reading ahead) and therefore I was thinking that couldn't be it.

At this point I don't even know where to begin. Should I attempt to make it fit into an active band pass filter? Or solve for the cut off frequencies by finding the magnitude of the transfer function and setting it equal to 1/sqrt(2).

I think I just need a nudge the right direction.

Thanks for any help!
 
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So I finally figured it out. Turns out if we multiply the transfer function by (30/30) we get a transfer function of
H(s)=[300s/(s^2+300s+10^6)](1/30) which fits our definition for an ideal band pass function. By simply comparing it with the format for the ideal band pass function we can determine all of the above parameters.
 

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