Cyclic and non proper subgroups

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1. What is/are the condition for a group with no proper subgroup to be cyclic?


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3. this is just a general qustion I am asking in oder to prove something?
 
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Let a be non-identity member of G. If for some n, an= e, then {a, a2, ..., an-1, an= e} is a subgroup of G.

Now if G has no proper subgroups what is the smallest such n for any a? What does that tell you about G?
 
I don't quite understand, but I'm guessing the smallest such n would be 1... can you give me an example of a Group with non proper subgroups
 
I think I figurd it out ...the smallest of such n would be distinct , the group itself would bconsist of elements of infinite order... I still need an example of a Cyclic group with non proper subgroups
 
Do you really understand what you are asking? Any group of prime order has no proper subgroup.
 
Not quite...Ok this is my problem:
If G has noroper subgroups, prove that G is cyclic.

Proof:
If G has no proper subgroup then |G|= p. For any nonidentity element a belonging to G, <a> is a subgroup of order greater than 1. By Langrange's Theorem, since |a|divides |G| |a| = p therefore, <a> = G and G is a cyclic group of order p.

Does this proof make sense? In your first question I sain that the smallest scuh n is 1 hence the reason why I said that |a| must be greater than one...I'm notre if my proof is correct but does it make sense?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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