I have a homwork question that I've been having some trouble with but have come up with a solution.. can someone please verify that i'm on the right path????
The homwork problem is here http://i51.tinypic.com/bbeaf.jpg
vx= vocos(theta) vy=vosin(theta)
constant vel equations for physics 1
The Attempt at a Solution
Spliting the motion into x-y axis
Horizontal: u= vocosα= 15cosα, a=0, d= 2.5 m
Vertical= u= u= vosinα= 15sinα, a= -9.8, d= 0.05 m
Horizontal: no acceleration so constant velocity time taken to reach to the center
t= 2.5/15cosα = 1/6cosα
-s = +(15sinα)t + 0.5*(-9.8)*t^2
-0.05 = +(15sinα) (1/6cosα) - 0.5*9.8*(1/6cosα)^2
-0.05 = +(2.5tanα) - 4.9/(36sec^2α)
-0.05 = +(2.5tanα) - 4.9(cos^2α) /36
Because angle is very small, cos^2 α ~ 1 .
-0.05= +(2.5tanα) - 4.9/36
α = tan^-1 (0.086)
α = 4.915 degree
in vertical motion,
Vertical: v=0 ; u= vosinα= 15sinα, a= -9.8, d= ?
02 = (15sin4.92)2 +2*-9.8d
D=8.444 cm (converted from 0.084m to cm)
Yoffset= 13.444 cm