To find potential differences in circuits with multiple batteries, Kirchhoff's Loop Rule is essential, stating that the sum of currents and voltages around a closed loop equals zero. This principle allows for the calculation of electric potential at specific points in the circuit. Resources and explanations on Kirchhoff's rules can provide further clarity on this topic. Understanding these concepts is crucial for analyzing complex DC circuits effectively. Utilizing Kirchhoff's Loop Rule simplifies the process of determining potential differences in such circuits.
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mackn666
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How do i find pottential differences between two points in such a circuit? Could anyone post a link to a page that can help explain such circuits, because i am greatly confused
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
The answer to this question is statements (ii) and (iv) are correct.
(i) This is FALSE because the speed of water in the tap is greater than speed at the water surface
(ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not?
(iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame?
I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...