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Homework Help: DC offset in amplifiers

  1. May 3, 2009 #1


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    1. The problem statement, all variables and given/known data
    Explain what is meant by "DC Offset" in an amplifier and how can you eliminate it ?

    2. The attempt at a solution
    I think it is the deviation from the real voltage, but I am not sure
  2. jcsd
  3. May 5, 2009 #2
    DC Offset is pretty much what the name suggests - there is an offset from 0V (DC, I assume) to some other voltage, say, 4V. I guess the best way to explain it is when you look at a scope diagram. For example, say you're looking at a waveform that looks like http://www.innovatia.com/Design_Center/DC_images/image707.gif [Broken]. The mean of the waveform (the dotted line) is above 0, and that height in the Y-axis is the offset.

    I remember dealing with this in my engineering lab. I think we used a capacitor to act as a filter to get rid of the DC offset. The reason that I think a capacitor works is that a capacitor is an open circuit to DC, so none of that offset voltage passes through it, giving you a "clean" waveform.

    http://www.innovatia.com/Design_Center/Electric_Circuits.htm [Broken]
    Last edited by a moderator: May 4, 2017
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