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dy/dx=(-x+sqrt(x^2+y^2))/y
USE SUBSTITUTION u=x^2+y^2
I tried to work it out but got a really ugly answer, please help!
USE SUBSTITUTION u=x^2+y^2
I tried to work it out but got a really ugly answer, please help!
I gotIf you use the correct substitution then several things should cancel. It would be helpful to also post your attempt at the solution in order to see where you are having problems.
du/dx would be 2x+2y but I dont understand where to go from there. how can I replace dy/dx with it?Instead of starting out by trying to separate and integrate, try finding an expression for du/dx and using it to replace dy/dx
Remember that you have to use implicit differentiation.du/dx would be 2x+2y but I dont understand where to go from there. how can I replace dy/dx with it?
I did it (in my head, not on paper yet) and I'm pretty sure I've got it! thank you so much, I appreciate all of your help!Remember that you have to use implicit differentiation.
[tex]du=2xdx+2ydy[/tex]
Then you can solve for [tex]dy/dx[/tex]
You should find that when you find this and substitute, several things should cancel.
nvm, I still can't get it. it's okay though, thank you, I appreciate all of your help!Remember that you have to use implicit differentiation.
[tex]du=2xdx+2ydy[/tex]
Then you can solve for [tex]dy/dx[/tex]
You should find that when you find this and substitute, several things should cancel.
[tex] \frac{du}{dx} = 2x+2y \, \frac{dy}{dx}[/tex]nvm, I still can't get it. it's okay though, thank you, I appreciate all of your help!
Thanks so much :)[tex] \frac{du}{dx} = 2x+2y \, \frac{dy}{dx}[/tex]
Now just substitute in your original expression for dy/dx and it literally just falls into place.