Decay of Alpha Particle Through Quantum Tunneling

OhMyGod
Messages
5
Reaction score
0

Homework Statement



By using the graph attached,
Why high energy alpha particles are emitted by alpha-emitters of short wavelength?


Homework Equations



Transmission Coefficient Equation : T=exp(-2kd)

The Attempt at a Solution



Ain't really sure. Can't really figure out why is the graph shaped like that in the first place.
Anyone wants to give it a shot into explaining what accounts for this the shape of the graph first?



Many thanks in advance :D
 

Attachments

  • phyquest.GIF
    phyquest.GIF
    2.5 KB · Views: 523
Physics news on Phys.org
i reckon the energy of the nucleons is very low in the well, ie the nucleons are most stable there (due to conditions given by strong nuclear force), the rapid peak indicates that outside this radius, the energetic stability is very low, hence peak energy value, this subsides with increasing distance inversely with distance - arising due to coulomb force.

so am i within the 10^-15m or have i missed the point, i am humble i can handle it.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top