Definite integral with x^2+c in the denominator

Hypatio
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Homework Statement

Homework Equations



solve the definite integral

\int_{2.6}^{5.5} \frac{1}{x^2+9}dx

The Attempt at a Solution



ln(5.5^2+9)-ln(2.6^2+9) doesn't seem correct
 
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Can you show your steps in getting that solution? What did you get for the antiderivative of the integrand?
 
Hypatio said:

Homework Statement




Homework Equations



solve the definite integral

\int_{2.6}^{5.5} \frac{1}{x^2+9}dx

The Attempt at a Solution



ln(5.5^2+9)-ln(2.6^2+9) doesn't seem correct

If you take the derivative of log(x^2+9) you will not get 1/(x^2+9) (at least if you don't forget the chain rule). You need a trig substitution to do that integral.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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